You have lear tastes of food are due to acids and bases, respectively, present in them. nt in your previous classes that the sour and bitter
If someone in the family is suffering from a problem of acidity after overeating, which of the following would you suggest as a remedy– lemon juice, vinegar or baking soda solution?
You already know that acids are sour in taste and change the colour of blue litmus to red, whereas, bases are bitter and change the colour of the red litmus to blue. Litmus is a natural indicator, turmeric is another such indicator. Have you noticed that a stain of curry on a white cloth becomes reddish-brown when soap, which is basic in nature, is scrubbed on it? It turns yellow again when the cloth is washed with plenty of water. You can also use synthetic indicators such as methyl orange and phenolphthalein to test for acids and bases.
In this Chapter, we will study the reactions of acids and bases, how acids and bases cancel out each other’s effects and many more interesting things that we use and see in our day-to-day life.
Litmus solution is a purple dye, which is extracted from lichen, a plant belonging to the division Thallophyta, and is commonly used as an indicator. When the litmus solution is neither acidic nor basic, its colour is purple. There are many other natural materials like red cabbage leaves, turmeric, coloured petals of some flowers such as Hydrangea, Petunia and Geranium, which indicate the presence of acid or base in a solution. These are called acid-base indicators or sometimes simply indicators.
These indicators tell us whether a substance is acidic or basic by change in colour. There are some substances whose odour changes in acidic or basic media. These are called olfactory indicators. Let us try out some of these indicators.
Which of these – vanilla, onion and clove, can be used as olfactory indicators on the basis of your observations?
Let us do some more activities to understand the chemical properties of acids and bases.
CAUTION: This activity needs the teacher’s assistance.
Note that the metal in the above reactions displaces hydrogen atoms from the acids as hydrogen gas and forms a compound called a salt.
Thus, the reaction of a metal with an acid can be summarised as –
Acid + Metal → Salt + Hydrogen gas
Can you now write the equations for the reactions you have observed?
The reaction that takes place can be written as follows.
\( \begin{align} & 2NaOH(aq)+Zn(s)\to N{{a}_{2}}Zn{{O}_{2}}(s)+{{H}_{2}}(g) \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(Sodium\,\,zincate) \\ \end{align} \)
You find again that hydrogen is formed in the reaction. However, such reactions are not possible with all metals.
The reactions occurring in the above Activity are written as –
Test tube A: \( N{{a}_{2}}C{{O}_{3}}(s)+2HCl(aq)\to 2NaCl(aq)+{{H}_{2}}O(\ell )+C{{O}_{2}}(g) \)
Test tube B: \( NaHC{{O}_{3}}(s)+HCl(aq)\to NaCl(aq)+{{H}_{2}}O(\ell )+C{{O}_{2}}(g) \)
On passing the carbon dioxide gas evolved through lime water,
\( \begin{align} & Ca{{(OH)}_{2}}(aq)+C{{O}_{2}}(g)\to CaC{{O}_{3}}(s)+{{H}_{2}}O(\ell ) \\ & (Lime\,\,water)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(White\,\,precipitate) \\ \end{align} \)
On passing excess carbon dioxide the following reaction takes place:
\( \begin{align} & CaC{{O}_{3}}(s)+{{H}_{2}}O(\ell )+C{{O}_{2}}(g)\to Ca(HC{{O}_{3}})(aq) \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(\text{Soluble}\,\,\text{in}\,\,\text{water}) \\ \end{align} \)
Limestone, chalk and marble are different forms of calcium carbonate. All metal carbonates and hydrogencarbonates react with acids to give a corresponding salt, carbon dioxide and water.
Thus, the reaction can be summarised as –
Metal carbonate/Metal hydrogencarbonate + Acid → Salt + Carbon dioxide + Water
In the above Activity, we have observed that the effect of a base is nullified by an acid and vice-versa. The reaction taking place is written as –
\( NaOH(aq)+HCl(aq)\to NaCl(aq)+{{H}_{2}}O(\ell ) \)
The reaction between an acid and a base to give a salt and water is known as a neutralisation reaction. In general, a neutralisation reaction can be written as –
Base + Acid → Salt + Water
You will notice that the colour of the solution becomes blue-green and the copper oxide dissolves. The blue-green colour of the solution is due to the formation of copper(II) chloride in the reaction. The general reaction between a metal oxide and an acid can be written as –
Metal oxide + Acid → Salt + Water
Now write and balance the equation for the above reaction. Since metallic oxides react with acids to give salts and water, similar to the reaction of a base with an acid, metallic oxides are said to be basic oxides.
You saw the reaction between carbon dioxide and calcium hydroxide (lime water) in Activity 2.5. Calcium hydroxide, which is a base, reacts with carbon dioxide to produce a salt and water. Since this is similar to the reaction between a base and an acid, we can conclude that nonmetallic oxides are acidic in nature.
1. Why should curd and sour substances not be kept in brass and copper vessels?
2. Which gas is usually liberated when an acid reacts with a metal? Illustrate with an example. How will you test for the presence of this gas?
3. Metal compound A reacts with dilute hydrochloric acid to produce effervescence. The gas evolved extinguishes a burning candle. Write a balanced chemical equation for the reaction if one of the compounds
formed is calcium chloride.
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